I've included a link if you're wanting to go back and remember how completing the square works. Remember, we just want to make the right side of the equation a perfect square trinomial (which is in the form of ax^2 + 2kx + k^2 --- don't worry too much about the k's. It's just to show you that your b value for the quadratic is just 2k and your c value for the quadratic is just k^2.
The idea behind Completing the Square
Steps:
1. get the equation so that you have x^2 + 2kx on the right, and = - c on the left.
2. Find your b term
3. Divide your b term by 2
4. Got that answer? Square it.
5. That's now your new c value (which we can also label as k^2).
Once you have that new c value, you factor the trinomial into it's perfect square factored form, take the square root of both sides of your equation, and solve for x (remember, that's your root!) Don't forget when we take the square root of a number, it's going to be either that number, or the negative of that number. ((-4)(-4) = 16 OR (4)(4) = 16).
EXAMPLES!
x2 – 2x – 48 = 0
x2 – 2x – 48 + 48 = 0 + 48
x2 – 2x =
48
Our b term is -2.
Half of -2 is -1, then we square that, and get (-1)2 = 1
x2 – 2x + 1 = 48 + 1
x2 – 2x + 1 = 49
(x + 1)(x + 1) = 49
(x + 1)2 = 49
sqrt((x + 1)2) = +/- sqrt(49)
(x + 1) = +/- sqrt(49)
So we have two situations:
either….
(x + 1) = + 7 OR
(x + 1) = - 7
x = 6 OR x = -8
Quadratic Formula:
Remember, it might look scary, but this thing is going to be your new best friend.
ax2 + bx + c = 0
The a, b, and c values from your equation just replace their respective letters in the formula.
Example:
x2 - 2x - 1 = 0
a = 1
b = -2
c = -1
x = -(-2) +/- sqrt( (-2^2) - 4(1)(-1)) / 2(1)
(Sorry, blogger doesn't like it when I try and type these equations to look beautiful in word and copy them into here - sqrt( ) is just the square root of whatever is in the parentheses!)
x = 2 +/- sqrt( 4 + 4 ) / 2
x = 2 + sqrt(8) / 2 OR x = 2 - sqrt(8) / 2
(Aside: We can break 8 into 2*4, and 4 is a perfect square, so we can take the square root of the 4 and leave the left over 2 under the square root, so it'll look something like, 2sqrt(2))
Since we can pull a factor of 2 out of both terms in the numerator (with the little amount of math magic / root properties), we find:
x = 2(1 + sqrt(2) / 2 OR x = 2(1 - sqrt(2)) / 2
The twos in the numerator and denominator cancel out, leaving us with:
x = 1 + sqrt(2) OR x = 1 - sqrt(2)
TADA!
Links!
NOTE: I really did record myself singing the quadratic formula song, but it's not uploading at the moment. I will figure it out, though!
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